6t^(-2/3)-t^(-1/3)-1=0

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Solution for 6t^(-2/3)-t^(-1/3)-1=0 equation:


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

6*t^(-2/3)-t^(-1/3)-1 = 0

t_1 = t^(-1/3)

6*t_1^2-1*t_1^1-1 = 0

6*t_1^2-t_1-1 = 0

DELTA = (-1)^2-(-1*4*6)

DELTA = 25

DELTA > 0

t_1 = (25^(1/2)+1)/(2*6) or t_1 = (1-25^(1/2))/(2*6)

t_1 = 1/2 or t_1 = -1/3

t_1 = -1/3

t^(-1/3)+1/3 = 0

1*t^(-1/3) = -1/3 // : 1

t^(-1/3) = -1/3

-1/3 < 0

1/(t^(1/3)) = -1/3 // * t^(1/3)

1 = -1/3*t^(1/3) // : -1/3

-3 = t^(1/3)

t^(1/3) = -3 // ^ 3

t = -27

t_1 = 1/2

t^(-1/3)-1/2 = 0

1*t^(-1/3) = 1/2 // : 1

t^(-1/3) = 1/2

-1/3 < 0

1/(t^(1/3)) = 1/2 // * t^(1/3)

1 = 1/2*t^(1/3) // : 1/2

2 = t^(1/3)

t^(1/3) = 2 // ^ 3

t = 8

t in { -27, 8 }

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